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d3-array
Edited
Oct 26, 2023
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11 stars
d3-array
Image Sharpeningd3.blurd3.rankd3.flatGroup, d3.flatRollupd3.moded3.groupSortSet Operationsd3.groups as a hierarchyd3.fsum, d3.AdderTime thresholds for d3.bind3.cumsumTidy Stacked Area ChartMerging Duplicate Valuesd3.zip, d3.transposed3.bind3.ticksd3.mean, d3.median, and friendsd3.quickselectd3.bisectd3.sumd3.group, d3.rollup, d3.index
d3.count
d3.min, d3.max, d3.extentd3.least, d3.greatestd3.pairsd3.crossd3.ascending, d3.descendingd3.merged3.ranged3.permuted3.shuffled3-array 2.0
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flights = [
{airline: "Icelandair", price: 1621, stops: 3},
{airline: "Multiple airlines", price: undefined, stops: 2},
{airline: "Air France", price: 1948, stops: 0},
{airline: "WestJet", price: undefined, stops: 1},
{airline: "Air France", price: 1951, stops: 1},
{airline: "French Bee", price: 1780, stops: 1}
]
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d3.count(flights, d => d.price)
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d3.mean(flights, d => d.price)
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d3.sum(flights, d => d.price) / d3.count(flights, d => d.price)
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d3.count([1, 2, undefined, 3, NaN, 4])
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d3.count(["I", "accidentally", undefined, "a", "word"])
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d3.count([new Date("2019-01-01"), new Date(NaN)])
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d3.count([1, 2, 3, "N/A"]) // 🌶
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d3.count(["1", "2", "3", "N/A"], d => +d) // 👍
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